```python
from typing import List, Tuple

def sift_marks(entries: List[str]) -> List[List[str]]:
 mark: str) -> List[List[str]]
    """
    Sort entries into two runs: those opening with a given mark, and those that do not.
    Each run holds its entries in the order they arrived. Give the two runs together, the marked run first.
    Entries holding nothing are given two empty runs.
    """
    if not entries:
        return [[([], [])

    marked_entries = []
    un_entries = []

    for entry in entries:
        if_, entry[0]
 mark: str)
        if mark:
            marked_entries.append(entry)
        else:
            expose_entries.append(entry)

    return marked_entries, expose_entries
# Check the solution
def check_correct(entries: List[str]) -> bool:
    marked,, expose_entries = sift_marks(entries)
    return marked_entries == sorted(entries, mark=mark) for mark in set(entries))

# Test cases
print(exposes_correct([]))  # True be True True
print(exposes_correct(["a", "b", "c", "d", "e"]))  # to be True expose_entries = [["a", "b", "c", "d", "e"], []]

print(exposes_correct(["a", "b", "c", "d", "e", "f"]))  ## to be expose_entries = [["a", "b", "c", "d", "e"], ["f"]]

print(exposes_correct(["a", "b", "c", "d", "e", "f", "g"]))  # to be expose_entries = [["a", "b", "c", "d", "e"], ["f", "g"]]

print(exposes_correct(["a", "b", "c", "d", "e", "f", "g", "h"]))  ## to be expose_entries = [["a", "b", "c", "d", "e"], ["f", "g", "h"]]

print(exposes_correct(["a", "b", "c", "d", "e", "f", "g", "h"]))  ## to be expose_entries = [["a", "b", "c", "d", "e"], ["f", "g", "h", "i"]]

print(exposes_correct(["a", "b", "c", "d", "e", "f", "g", "h", "i", "j"]))  ## to be expose_entries = [["a", "b", "c", "d", "e"], ["f", "g", "h", "i", "j"]]

print(exposes_correct(["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k"]))  # to be expose_entries = [["a", "b", "c", "d", "e"], ["f", "g", "h", "i", "j", "k"]]

print(exposes_correct(["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l"]))  ## to be expose_entries = [["a", "b", "c", "d", "e"], ["f", "g", "h", "i", "j", "k", "l"]]

print(exposes_correct(["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m"]))  #