```python
def grid_flip(grid: list) -> list:
    """Return the grid turned so that its columns become its rows.
    
    The first row of the result holds the first value of every row in order.
    A grid with no rows gives an empty grid.
    """
    if not grid:
        return []
    
    # Determine the maximum row length to handle rows of differing lengths
    max_len = max(len(row) for row in grid)
    
    # Transpose the grid: for each column index, collect the element from each row
    result = []
    for col_idx in range(max_len):
        new_row = []
        for row in grid:
            if col_idx < len(row):
                new_row.append(row[col_idx])
            else:
                # If a row is shorter, we need to decide how to handle it.
                # Since the contract doesn't specify, we'll include None or skip?
                # Standard zip behavior stops at the shortest. But "first value of every row"
                # implies we should handle all rows. If a row doesn't have a value at col_idx,
                # it's ambiguous. However, typically in such problems, if rows differ in length,
                # we might pad or truncate. Let's look at the description again:
                # "the first row of the answer holds the first value of every row in order"
                # This implies that if a row doesn't have a first value, it's an issue.
                # But the contract says "Whether rows of differing lengths should be handled is not stated."
                # So I will assume standard behavior: if a row is shorter, we just take what's there?
                # No, that would break the "column becomes row" structure if we just skip.
                # Let's assume we pad with None for missing values to maintain the rectangular structure
                # of the transposed grid, or we truncate to the shortest row?
                # Actually, the most robust interpretation of "grid" is a rectangular structure.
                # If it's not rectangular, the output shape is ambiguous.
                # Given the ambiguity, I'll implement a version that pads with None for missing elements,
                # as this preserves all data.
                new_row.append(None)
        result.append(new_row)
    
    return result
```