Coverage for /usr/lib/python3/dist-packages/sympy/functions/elementary/_trigonometric_special.py: 25%
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« prev ^ index » next coverage.py v7.9.1, created at 2025-06-14 15:55 +0200
1r"""A module for special angle forumlas for trigonometric functions
3TODO
4====
6This module should be developed in the future to contain direct squrae root
7representation of
9.. math
10 F(\frac{n}{m} \pi)
12for every
14- $m \in \{ 3, 5, 17, 257, 65537 \}$
15- $n \in \mathbb{N}$, $0 \le n < m$
16- $F \in \{\sin, \cos, \tan, \csc, \sec, \cot\}$
18Without multi-step rewrites
19(e.g. $\tan \to \cos/\sin \to \cos/\sqrt \to \ sqrt$)
20or using chebyshev identities
21(e.g. $\cos \to \cos + \cos^2 + \cdots \to \sqrt{} + \sqrt{}^2 + \cdots $),
22which are trivial to implement in sympy,
23and had used to give overly complicated expressions.
25The reference can be found below, if anyone may need help implementing them.
27References
28==========
30.. [*] Gottlieb, Christian. (1999). The Simple and straightforward construction
31 of the regular 257-gon. The Mathematical Intelligencer. 21. 31-37.
32 10.1007/BF03024829.
33.. [*] https://resources.wolframcloud.com/FunctionRepository/resources/Cos2PiOverFermatPrime
34"""
35from __future__ import annotations
36from typing import Callable
37from functools import reduce
38from sympy.core.expr import Expr
39from sympy.core.singleton import S
40from sympy.core.numbers import igcdex, Integer
41from sympy.functions.elementary.miscellaneous import sqrt
42from sympy.core.cache import cacheit
45def migcdex(*x: int) -> tuple[tuple[int, ...], int]:
46 r"""Compute extended gcd for multiple integers.
48 Explanation
49 ===========
51 Given the integers $x_1, \cdots, x_n$ and
52 an extended gcd for multiple arguments are defined as a solution
53 $(y_1, \cdots, y_n), g$ for the diophantine equation
54 $x_1 y_1 + \cdots + x_n y_n = g$ such that
55 $g = \gcd(x_1, \cdots, x_n)$.
57 Examples
58 ========
60 >>> from sympy.functions.elementary._trigonometric_special import migcdex
61 >>> migcdex()
62 ((), 0)
63 >>> migcdex(4)
64 ((1,), 4)
65 >>> migcdex(4, 6)
66 ((-1, 1), 2)
67 >>> migcdex(6, 10, 15)
68 ((1, 1, -1), 1)
69 """
70 if not x:
71 return (), 0
73 if len(x) == 1:
74 return (1,), x[0]
76 if len(x) == 2:
77 u, v, h = igcdex(x[0], x[1])
78 return (u, v), h
80 y, g = migcdex(*x[1:])
81 u, v, h = igcdex(x[0], g)
82 return (u, *(v * i for i in y)), h
85def ipartfrac(*denoms: int) -> tuple[int, ...]:
86 r"""Compute the the partial fraction decomposition.
88 Explanation
89 ===========
91 Given a rational number $\frac{1}{q_1 \cdots q_n}$ where all
92 $q_1, \cdots, q_n$ are pairwise coprime,
94 A partial fraction decomposition is defined as
96 .. math::
97 \frac{1}{q_1 \cdots q_n} = \frac{p_1}{q_1} + \cdots + \frac{p_n}{q_n}
99 And it can be derived from solving the following diophantine equation for
100 the $p_1, \cdots, p_n$
102 .. math::
103 1 = p_1 \prod_{i \ne 1}q_i + \cdots + p_n \prod_{i \ne n}q_i
105 Where $q_1, \cdots, q_n$ being pairwise coprime implies
106 $\gcd(\prod_{i \ne 1}q_i, \cdots, \prod_{i \ne n}q_i) = 1$,
107 which guarantees the existance of the solution.
109 It is sufficient to compute partial fraction decomposition only
110 for numerator $1$ because partial fraction decomposition for any
111 $\frac{n}{q_1 \cdots q_n}$ can be easily computed by multiplying
112 the result by $n$ afterwards.
114 Parameters
115 ==========
117 denoms : int
118 The pairwise coprime integer denominators $q_i$ which defines the
119 rational number $\frac{1}{q_1 \cdots q_n}$
121 Returns
122 =======
124 tuple[int, ...]
125 The list of numerators which semantically corresponds to $p_i$ of the
126 partial fraction decomposition
127 $\frac{1}{q_1 \cdots q_n} = \frac{p_1}{q_1} + \cdots + \frac{p_n}{q_n}$
129 Examples
130 ========
132 >>> from sympy import Rational, Mul
133 >>> from sympy.functions.elementary._trigonometric_special import ipartfrac
135 >>> denoms = 2, 3, 5
136 >>> numers = ipartfrac(2, 3, 5)
137 >>> numers
138 (1, 7, -14)
140 >>> Rational(1, Mul(*denoms))
141 1/30
142 >>> out = 0
143 >>> for n, d in zip(numers, denoms):
144 ... out += Rational(n, d)
145 >>> out
146 1/30
147 """
148 if not denoms:
149 return ()
151 def mul(x: int, y: int) -> int:
152 return x * y
154 denom = reduce(mul, denoms)
155 a = [denom // x for x in denoms]
156 h, _ = migcdex(*a)
157 return h
160def fermat_coords(n: int) -> list[int] | None:
161 """If n can be factored in terms of Fermat primes with
162 multiplicity of each being 1, return those primes, else
163 None
164 """
165 primes = []
166 for p in [3, 5, 17, 257, 65537]:
167 quotient, remainder = divmod(n, p)
168 if remainder == 0:
169 n = quotient
170 primes.append(p)
171 if n == 1:
172 return primes
173 return None
176@cacheit
177def cos_3() -> Expr:
178 r"""Computes $\cos \frac{\pi}{3}$ in square roots"""
179 return S.Half
182@cacheit
183def cos_5() -> Expr:
184 r"""Computes $\cos \frac{\pi}{5}$ in square roots"""
185 return (sqrt(5) + 1) / 4
188@cacheit
189def cos_17() -> Expr:
190 r"""Computes $\cos \frac{\pi}{17}$ in square roots"""
191 return sqrt(
192 (15 + sqrt(17)) / 32 + sqrt(2) * (sqrt(17 - sqrt(17)) +
193 sqrt(sqrt(2) * (-8 * sqrt(17 + sqrt(17)) - (1 - sqrt(17))
194 * sqrt(17 - sqrt(17))) + 6 * sqrt(17) + 34)) / 32)
197@cacheit
198def cos_257() -> Expr:
199 r"""Computes $\cos \frac{\pi}{257}$ in square roots
201 References
202 ==========
204 .. [*] https://math.stackexchange.com/questions/516142/how-does-cos2-pi-257-look-like-in-real-radicals
205 .. [*] https://r-knott.surrey.ac.uk/Fibonacci/simpleTrig.html
206 """
207 def f1(a: Expr, b: Expr) -> tuple[Expr, Expr]:
208 return (a + sqrt(a**2 + b)) / 2, (a - sqrt(a**2 + b)) / 2
210 def f2(a: Expr, b: Expr) -> Expr:
211 return (a - sqrt(a**2 + b))/2
213 t1, t2 = f1(S.NegativeOne, Integer(256))
214 z1, z3 = f1(t1, Integer(64))
215 z2, z4 = f1(t2, Integer(64))
216 y1, y5 = f1(z1, 4*(5 + t1 + 2*z1))
217 y6, y2 = f1(z2, 4*(5 + t2 + 2*z2))
218 y3, y7 = f1(z3, 4*(5 + t1 + 2*z3))
219 y8, y4 = f1(z4, 4*(5 + t2 + 2*z4))
220 x1, x9 = f1(y1, -4*(t1 + y1 + y3 + 2*y6))
221 x2, x10 = f1(y2, -4*(t2 + y2 + y4 + 2*y7))
222 x3, x11 = f1(y3, -4*(t1 + y3 + y5 + 2*y8))
223 x4, x12 = f1(y4, -4*(t2 + y4 + y6 + 2*y1))
224 x5, x13 = f1(y5, -4*(t1 + y5 + y7 + 2*y2))
225 x6, x14 = f1(y6, -4*(t2 + y6 + y8 + 2*y3))
226 x15, x7 = f1(y7, -4*(t1 + y7 + y1 + 2*y4))
227 x8, x16 = f1(y8, -4*(t2 + y8 + y2 + 2*y5))
228 v1 = f2(x1, -4*(x1 + x2 + x3 + x6))
229 v2 = f2(x2, -4*(x2 + x3 + x4 + x7))
230 v3 = f2(x8, -4*(x8 + x9 + x10 + x13))
231 v4 = f2(x9, -4*(x9 + x10 + x11 + x14))
232 v5 = f2(x10, -4*(x10 + x11 + x12 + x15))
233 v6 = f2(x16, -4*(x16 + x1 + x2 + x5))
234 u1 = -f2(-v1, -4*(v2 + v3))
235 u2 = -f2(-v4, -4*(v5 + v6))
236 w1 = -2*f2(-u1, -4*u2)
237 return sqrt(sqrt(2)*sqrt(w1 + 4)/8 + S.Half)
240def cos_table() -> dict[int, Callable[[], Expr]]:
241 r"""Lazily evaluated table for $\cos \frac{\pi}{n}$ in square roots for
242 $n \in \{3, 5, 17, 257, 65537\}$.
244 Notes
245 =====
247 65537 is the only other known Fermat prime and it is nearly impossible to
248 build in the current SymPy due to performance issues.
250 References
251 ==========
253 https://r-knott.surrey.ac.uk/Fibonacci/simpleTrig.html
254 """
255 return {
256 3: cos_3,
257 5: cos_5,
258 17: cos_17,
259 257: cos_257
260 }